Page
6
"There
was nothing of any great significance or
originality in these accounts , and they followed the
pattern of many other sightings .However from the mass of
detail supplied by so many different people over so wide an
area, it was possible to plot the track of the object with
reasonable accuracy. I started work on a Mercator's plotting
chart and after several hours of checking one report against
the other, and calculating possible elevations and
trajectories I felt
I
had refined the plot sufficiently to draw in the final track
of the object, or objects. The result is shown on map
1"
Page
7
"
Map
1 Showing section of first trackline discovered of world
grid system .This map was originally published in my first
book, Harmonic 33,
in 1968. The trackline extends from the position of a USO
sighted in the Kaipara Harbour, Aukland, to a position at
D'Urville Island where two large UFO's were seen
to disappear in a flash of light.
The
scribe finding the way ahead confusing asked the Zed Aliz
Zed if they were on the right track of the
that
of
where they went .
Keep your head down scribe said the Zed Aliz Zed and
follow that not so sad
sad blind ass of serendip
Page
8
"The
track began about seventy nautical miles north of New
Plymouth, passed just to the west of Mt Egmont, and finished
at D'Urville Island."
"
I pored over that plot for a long time before it suddenly
occurred to me that the track appeared in line
with the position where I had sighted the unidentified
submarine object or USO on 12 March 1965. On extending the
line back Ifound it was in line with the sightings of 26
March . I was positive there had to be a connectionbut to
prove it was a different
matter.
I
checked my report files again and found that on 2 March some
fishermen just north of the coast at New Plymouth had seen a
large object plunge into the water and disappear.They
thought it was an aircraft and reported the incident to the
appropriate authorities, but no aircraft or personnel was
missing. I checked this position on the map and found that
it also fitted the established trackline. Was this connected
with the USO of 12 March and could the two sightings be the
same object, sighted twice in ten days
.
It
was some days later that I remembered the UFO I had seen in
1956. This object was similar and, most significant of all,
both objects had travelled at 90
* to
each other, and finished in the same grand allilluminating
flash in the area of D'Urville Island.
"
Page
9
"
If these objects were not controlled, how could
anyone explain such coincidence? No two meteors or other
natural phenomena could coincidentally carry out
similar manoeuvres, travel at 90*to
each other, and both decide to end there existence at the
same point in space, within nine
years
of each other…"
"I
plotted the track of the 1956 UFO on the map at
90*to
the northsouth line. I realised that I had no definite
proof that they were at exactly
90*
to each other or that the 1956 track was not a few miles
north or south of this
position
still,
I had to start from somewhere, and I would assume
this to be correct unless and until other evidence proved me
wrong "
Page
9
"
Two track lines at 90* meant little on their own .If I found
several at 90*, I might have somethinga grid
perhaps
?
These
two lines hinted at this, and I believed that if I could
solve the system of measurement, then I had two readymade
baselines to work
from.
Once
again I went to the UFO files and found that a Frenchman by
the name of Aime Michel had been studying UFOs for a number
of years and had found small sections of tracklines in
various parts of Europe…"
"…and Mr
Michel had observed that the average distance between
these points was 54.43
kilometres…"
Page
9
"Using
the Kaipara Harbour as a starting point, I marked off the
54.43 kilometre intervals along the trackline Ihad found. I
was disappointed when I was unsucessful in
obtaining an even distribution of positions to the D'Urville
Island disappearing point. I
checked and rechecked, but nothing worked out .I
slept on the problem, and at some time during the night
inspiration turned up the wick ; and once more the light
grew bright ."
I
remembered that a great number of sightings had occurred
around the Blenheim area."
Page
10
So
I dragged out my map and extended the track line until it
cut a 90* coordinate from the town of Blenheim the distance
from this point to the Kaipara position I found to be
exactly 300 nautical miles. So far so good. I stepped
off
The
54.3 kilometre intervals and swore. Still the thing
didn't fit ! "
"
Michel had found the interval of 54.43 kilometres in the
northern hemisphere. The earth is slightly pearshaped, and
a nautical mile is the
measurement of a minute of arc on the earth's
surface;
so
a nautical mile could be slightly longer in the
southern hemisphere, due to the distortion of the earth
itself. I found 55.5 kilometres to be equal to 30 nautical
miles and this divides exactly into 300 nautical miles, ten
times.
Was
this the system
of
measurement used by the UFOs. There was no proof of course ,
but it seemed a reasonable assumption. A minute of arc is a
measure which could apply to the whole universe .
It just so happens that a minute of arc from the earth's
centre subtends, at the surface, what we call a nautical
mile. So be it….
Since
I made that statement in my first book I have been attacked
repeatedly by university personnel and others in the
academic field. They have maintained that degrees and
minutes of arc are arbitary values set up by the ancient
mathematicians and that my calculations are meaningless. I
believe that evidence shown in this my third book will now
convince them that my original assumptions were correct. The
angular values of 360*
and 21,600
minutes of arc which constitute a complete circle have
direct geometric associations with the speed of light
(as
shown in Chapter Three).
The
fifth interval of 30 nautical miles from the
Kaiparaposition coincided with the position off the coast
of New Plymouth where the mysterious object had plunged
into the sea. The plotted points of disappearance of the two
large UFOs at D' Urville Island did not quite match up with
the ninth interval ,but this did not worry me unduly as I
expected that a small percentage of error must be expected
in my original plot. I readjusted this position to the ninth
interval, and carried on the search to see how many other
sightings I could fit into this pattern.
"
Page
11
"
The results exeeded my expectations. I found that by using
units of 30 minutes of arc latitude northsouth, and 30
minutes of arc longtitude eastwest, on my Mercator's map a
grid pattern was formed into which a great number of UFO
reports could be fitted.I eventually had a map with sixteen
stationary and seventeen moving UFOs plotted on grid
intersections and tracklines.
Having
satisfied myself that my reasoning and plotting were not
false. I considered that I had good proof that New Zealand,
possibly other countries, and probably the whole
world, were being systematically covered by some type of
grid system (see grid map 2 ).
In
my first book I demonstrated that the main grid pattern
consisted of grid lines spaced at intervals of 30 minutes of
arc (latitude and longtitude ). In my second book I probably
confused the issue a bit as I stated that the eastwest grid
lines were spaced at 24 minutes of arc. This was due to the
spacing being measured in nautical miles,or values in
minutes of latitudes. The actual length of a minute of
longtitude varies mathematically from one nautical mile at
the equator, to zero at the north and south
poles.
The
value of 30 minutes of arc in terms of longtitude in the New
Zealand area happened to be an average of 24 nautical miles,
which can be confusing to those readers who are not familiar
with map scales. Reference to the
grid structure will therefore be stated from now on in
minutes of arc values only, for latitude and longtitude, to
minimise confusion.
I
subsequently discovered that the grid lattice could be
further divided . It is now evident that the grid lines in
the main system are spaced at intervals of 7.5 minutes of
arc northsouth and eastwest. The importance of this will
prove itself when compared with the rest of the calculations
in this book. There are 21.600
minutes of arc in a circle, and when this is divided by
7.5we get a value of 2880.
The grid lattice therefore is tuned harmonically to twice
the speed of light (288),
as will be shown in other
sections
It
appeared that I had found a section of a geometric grid in
the New Zealand area. I now had to form some theory of
construction for the whole world. I could then possibly fit
the New Zealand section into
it.
By
drawing a series of patterns on a small plastic
ball I finally found a system which could be used as a
starting point for a global investigation. (The basic
pattern is shown in diagram 1.)
I
was sure I was on the right track but I now had to
superimpose this pattern on the world globe .It was
essential that I find a point position somewhere
on the earth upon which to orientate the geometrical
pattern. I finally came upon an item of news that gave me a
very important clue on how to
proceed.
On
29 August 1964 the American survey ship
Eltanin was carrying out a sweep of the sea bed off
the coast of South America. A series of submarine
photographs was being taken of the area by means of a long
cable attached to a long cable. A surprise was in store when
these photographs were developed On one of the
points, in marvellous detail, was an aerialtype object
sticking up from an otherwise featureless
seabed.
This
object appeared to be metallic and perfectly symetrical in
construction."
"…The
position where this object was found was given as latitude
59* 08 south, longtitude 105*
west.
"…
In view of my earlier sightings in the Kaipara Harbour , I
was willing to accept that the aerial type object had been
placed there by an unidentified submarine object , or
USO."
Page
14
"Diagram
1 Showing relationship of grid structure to the geographic
poles. Each of the two grids has a similar pattern, the
interaction of which sets up a third resultant grid. The
poles of the three grids are positioned at three different
latitudes and longtitudes ."
On the same page, alongside the actual diagram is the
following.
C,D,E,F
= Corner aerial positions of grid polar square .Similar to
aerial discovered by the survey ship
Eltanin
JK = Polar axis
A = Geographic pole
B = Grid pole
Distance
CGD = 3600
minutes of arc
Distance
CHD = 3418.5 minutes of arc
Distance CID =
3643.2
minutes of
arc
( 36003418.5
= 181.5 ) ( 181.5 x 4 = 726 ) ( / 726
= 26944
)
Reciprocal
of 36432
=
27448397
(
27448397
(
972 = 28239 ) (28.
239 = Gravity acceleration
harmonic)
(
3643
.
2  3600 = 43.2 ) (
43.
2 x 4 = 172 .
8
) (
172
.
8 = 2.
88*
) (288
= 2C )
Page
15
"…I
centred the grid on the position of the object found by the
Eltanin,and the 180*reciprocal
of this in Russian Siberia, lining the whole thing up with
the section I had found in New Zealand. I found the system
to be lined up very closely with the magnetic field of the
earth .The equator of the grid followed very closely the
line of zero dip around the world.(That is the positions on
the earth's surface where a magnetic compass needle has only
a horizontal and no vertical
)
In
my first two books I discussed the methods I used to line up
the system and calculate the first estimates of the
grid
Pole
positions, and the major focal points of the grid similar to
the Eltanin "aerial" placement . The
reciprocal position of the Eltanin "aerial" is at
latitude 59* 08 north , longtitude 75*east, in Siberia. I
calculated
The
length of the diagonal of what I call for simplicity, the "
polar grid square "and found it to be 5091. 168825 minutes
of arc long .I plotted a track from the Siberian position
through the north geographic pole and measured off this
distance to locate another corner aerial of the polar
square.( Square is not technically the right word to use as
the four sides are formed by sections of small circles which
are in different planes to each other. When the "polar
square" areas are transferred from the surface of
the earth sphere on to a flat plane such as a map, then a
perfect square is formed with sides 3600 minutes long and
diagonals of 5091.168825 minutes of arc.)
In
my first two books I stated in error, that the sides of the
"polar squares"were formed by sections of GREATcircles 3600
minutes of arc long, instead of SMALL circles. The great
circle distance between these points is in fact
3,418.5
minutes
of arc, which is very confusing to any investigator
attempting to reconstruct the grid I apologise to my
readers for this error, which was caused by my lack of
access to calculators during my earlier research. In the
grid pattern there are actually two smallcircle
/ Page
16 Diagram 2
Page 17 Diagram 3
Continuation
from page 15
Page
18 /
segments,
and one greatcircle segment connecting each of these points
which form the polar squares. Each of the segments has a
different path over the earth and some tricky calculating is
necessary to ascertain the true length. Although I used the
wrong term in my earlier publications, the actual
calculations derived from the grid system has not altered in
any way, and still stand the test of time. Over the last few
years I have slightly refined these values I demonstrated
previously, derived from a mixture of practical and
theoretical studies I have now set up what I see
as a completely theoretical system , discovered
by working entirely by calculator. Time will prove how close
my calculations are. I have no doubt that I, and others will
continue further to perfect the system as more facts come to
light .
Once
I had established this first baseline I found it quite easy
to construct the main skeleton of the grid over the whole
surface of the earth
.
As my
work progressed
I
found that there were in fact two similar grids, interlocked
with each other. The poles of the grids were
spaced at different distances from the north geometric pole,
and this arrangement set up a series of geometric harmonics
which were directly related to the speed of light, of mass,
and gravity. The interaction of the two grids created a
harmonic resonance which, in turn , formed a third resultant
grid.
After
ten years of work and correlating information I have now
calculated theoretical positions for the three grid poles in
the northern hemisphere which are very close to my original
estimates. Reciprocal positions will give similar values for
the southern
hemisphere:
Grid
pole "A" = Latitude 72.4266* / longtitude 90.6* west
1054.4
minutes of arc from the
NorthPole.
Grid
pole "B" = Latitude 78.4266*/ longtitude
105* west 694.4
minutes of arc from the North
Pole
Resultant
grid pole "C " = Latitude 75.6 / longtitude 97.8*
west 864
minutes of arc from the North Pole.
Page
19
The
values of 1054.4,
694.4 and
864
fall on spacial curves which have direct harmonic
associations as follow:
1054.
4
= Appears
to be associated with the harmonic crosssectional area of
all atoms.
694.4
= Harmonic of the speed of light reciprocal
1/C
864' =
14.4* = Harmonic of the speed of light.
The
longtitudinal separation of Grid A and Grid B is
also 14.4*,which
sets up another direct harmonic with the speed of light. The
separation creates a phasedifference harmonically tuned to
the circumference of the atom. I have shown in Chapter Five
that the harmonic circumference of all atomic structures is
a constant of 1152
units The spacing of the grid lines in each of Grids "A"and
"B" is 7.5 minutes of arc . If the angle of seperation of
the two grids of 14.4*,
or 864
minutes
of arc, is divided by the gridline spacing
of 7.5 minutes of arc we get
115.2
units, or (1152
harmonic). When this harmonic is applied to the
circumference of an atom it denotes the eight possible
electron positions spaced at 144
units
apart . In other words, each electron in an atomic shell is
spaced at the speed of light harmonic
144
units from its
neighbour.
[ 144
x 8 = 1152 ]
The
diagonal of the "polar square"of 5091.168825
units can be broken down into a series of
values:
5091.168824
(
2
= 2545.584412
2545.584412
( 7.5
= 3.39411255
3.39411255/2
= 11.52
11.52
(8 = 1.44 (speed of light
harmonic)
2545.584412/2
= 6480000
Reciprocal
of 2545.584412 = .03928371
The
number 648
is
a harmonic factor of great importance, as will be
demonstrated in other sections of this
book.
The
many other harmonic factors, centred around the "polar
square" corner "aerial "positions form a series of complex
mathematical associations, and this can be left for those
who wish to carry out their own research. If I can show
how to
/
Page
20
construct
the main "bones"of the grid my part of the job will be
complete
Page
21
The
conversion factors for ascertaining gravity
acceleration in grid terms are as
follow:
One
minute of arc is equal to 6000 grid feet, or 60806083
British feet so an average conversion factor to convert
British feet to grid feet would be to multiply the number by
.9865987, or 6000/6081.5.
The
grid time factor I discovered has stood up to scrutiny over
the years and is based on 27
periods for one revolution of the earth. Normally we use
24
periods of one hour each. The 27
periods, I call 27
grid hours. A grid hour is slightly shorter than a normal
hour, and is divided into sixty grid minutes, each of which
is equal to sixty grid seconds.
Therefore
for one revolution of the earth we have a standard time of
86,400 seconds as against a grid time of
97,200
Seconds.
The ratio is 8
:
9.
The
physics books state that gravity acceleration varies
/
Page
22 /
according
to latitude on the earths surface, and also with altitude,
or distance from the centre of the earth
.
The
variation at sea level from 0* to 90* latitude is equal to
32.087829 feet / second 2 to 32.257711 feet / second
2
I
decided to calculate the grid gravity
acceleration at a latitude of 52.88* which is 37.12*from the
geometric pole
The
288
harmonic
is evident here plus the harmonic of 3712, the reciprocal of
which is 2693966 (2694 ). If we interpolate the standard
gravity acceleration at this latitudeas 32.2015425 feet
/second 2 we can convert to grid gravity acceleration as
follows:
32
. 2015425
x 6000 x
8
= 28.239 grid feet /grid sec.
2
6081.5
9
We
can now manipulate the grid gravity acceleration factor of
28.239 as a harmonic of 28239:
28239
x 60 = 169434 (16944
)
28239 x 97200
= 274483
the
reciprocal
of 274483
= 36432
The
harmonic of 169434 is associated with the mass of the proton
in the atomic nucleus,
and 36432 is
built into
the
grid as a distance along the line of latitude between the
corner aerial positions of the "polar
squares"(3643.2)
(see
diagram 1). As can be seen the harmonics are evident when
different time periods for the acceleration factor are
considered.
In
my second book I stated that the first glimmerings of
how true space travel might be achieved came to
me when I uncovered the clues that led me to the UFO grid
which laces about our
globe.
I
was aware that my calculations were not precisely
accuratein the strict mathematical sensebut I could see
that the system was based on spacetime geometrics, and at
least there was the best possible support for this: non less
than the theories of
Einstein.
Somewhere,
I knew, the system contained a clue to the truth of the
unified field which, he had postulated permeates all of
/
Page
23 /
existence.
I didn't know at the time that this clue had already been
found by scientists who were well ahead of me . I know now
that they must have understood something of the grid system
years ago. They knew that Einstein's ideas about the unified
field were correct. What's more, for many years they had
been carrying out fullscale research into the practical
applications contained in that theory.
We
were told that Einstein died without completing his
equations relating to the unified field theory.But in more
recent times it has been said that he did in fact complete
his work but that the concepts were so advanced that the
full truth was not released.
The
only way to traverse the vast distances of space is to
possess the means of manipulating, or altering, the very
structure of space itself; altering the spacetime geometric
matrix, which to us provide the illusion of form and
distance. The method of achieving this lies in the
alteration of frequencies controlling the
matter
antimatter cycles which govern our awareness of
position in the spacetime
structure. Time itself is a geometric, just as Einstein
himself postulated; if time can be altered, then the whole
universe universe is waiting for us to come and explore its
nooks and crannies.
In
the blink of an eye we could cross colossal distances; for
distance is an illusion. The only thing that keeps places
apart in space is time. If it were possible to move from one
possible to move from one position to another in
space,
in
an infinitely small amount time or "zero time",
then both the positions would coexist according
to our awareness.
By
speeding up the geometric of time we will be able to bring
distinct places within close proximity. This is the secret
of the UFO'sthey
travel by altering the spatial dimensions around them and
repositioning in
spacetime
I
decided to concentrate specifically on
three
harmonic values which appeared to have a close relationship
with each other. Previously I had shown this connection and
had truthfully pointed out that I did not know why the
relationship was there at all.
On hearing this The scribe saw from out the corner of the
one good eye the ZedAlizZeds ears prick up. Oddthat could be
a dog, growled the thought.
